If there are n numbers of which one is (11n5) and all the others are 1s, then by how much is the arithmetic mean of these numbers less than 1.


Answer:

1n6

Step by Step Explanation:
  1. It is given that there are n numbers of which one is (11n5) and all the others are 1s.
    Therefore, the numbers are (11n5),1,1,1 (where n is the total number of numbers in the series)
  2. Out of n numbers one is (11n5) and remaining n1 numbers are 1.
    Therefore, the sum of n1 numbers is n1.
    Now, the sum of all numbers in the series =n1+(11n5)=n1n5
  3. Now, the arithmetic mean of the numbers =  
    Sum of the all numbers
    n
     
    =n1n5n
    =nn1n6
    =11n6
  4. Thus, we can say that the arithmetic mean of these numbers is 1n6 less than 1.

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