Suppose that a,b,ca,b,c are distinct numbers such that (cb)24(ca)(ab)=0,(cb)24(ca)(ab)=0, find the value of caab.caab.


Answer:

11

Step by Step Explanation:
  1. Given, (cb)24(ca)(ab)=0,(cb)24(ca)(ab)=0, we need to find the value of caab.caab.
  2. (cb)24(ca)(ab)=0(ca+ab)24(ca)(ab)=0((ca)+(ab))24(ca)(ab)=0(ca)2+(ab)2+2(ca)(ab)4(ca)(ab)=0(ca)2+(ab)22(ca)(ab)=0((ca)(ab))2=0(ca)(ab)=0(ca)=(ab)caab=1

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