There is a sequence of numbers a1, a2, ... where a1 = 2, a2 = 3, and an =
an-1 |
an-2 |
Answer:
Step by Step Explanation:
2 |
3 |
Step by Step Explanation:
- A series of number is given. Where a1 = 2 a2 = 3 and an =
for n ≥ 3.an-1 an-2 - On relating the sequence, a1 = 2
a2 = 3
a3 =
=a2 a1 3 2
a4 =
=a3 a2 1 2
a5 =
=a4 a3 1 3
a6 =
=a5 a4 2 3
a7 =
= 2a6 a2
a8 =
= 3a7 a6
and so on.... - Therefore, we will get a sequence which repeat after every sixth term,
i.e. a1 = 2, a2 = 3, a3 =
, a4 =3 2
, a5 =1 2
, a6 =1 3
, a7 = 2, a8 = 3 ....2 3 - As we have to find out a756. On dividing 756 by 6 which leaves a remainder of 0. So this term is equivalent to 6th term i.e. a6.
- Thus, a756 = a6 =
.2 3